Newtons Gravitational Law Assignment Help

Classical Physics- Newtons Gravitational Law

Newtons Gravitational Law

Newton in 1665 formulatedF α m1m2

∝ 1 / r2F = Gm1m2/ r2where G = 6.67 x 10-11.Its unit isNm-2and is called universal gravitational constant. The value of G was first experimentally determined by Cavendish in 1736. The value of G measured for small distances is about 1% less than the value ofGmeasured for large distances.

Gravitational field intercity gravitational force per unit mass is called gravitational field intensity. Gravitational field intensity of earth isg

E8= F / m = GM / r2

Gravitational potential(Vg)the amount of work done to bring a unit mass form infinity to that point under the influence of gravitational field of a given massM, without changing the velocity.

Vg= GM /r

Gravitational potential energy the amount of work done to bring a mass m from infinity to that point under the influence of gravitational field of a given massMwithout changing the velocity.

Ug= - GMm / r note that W = ?Ugand Ug= mVg.

Gravitational field intensity due to a ring of radius R, mass M, at any point on the axial line at a distance x from the centre of the ring is

Eg= G M .x / (R2+ x2)3/2

Gravitational field intercity inside the shell– 0

Eg= 2 GM / R2[1 – x / x2+ R2]2GM / R2[ 1 – cos θ]

In terms of angleθ.

Gravitational field intensity inside the shell = 0,

E surface = GM / R2

Gravitational potential due to a shell

Vin = V sur = - GM / r (x ≤ r)

V out = - GM / x (x > r)


Gravitational potential due to a solid sphere

V in = - GM / 2 R3(3 R2– r2) V out = -- GM / x (x > R)

V centre = - 3 GM / 2R

Gravitational field due to a solid sphere

E sur = GM /R2, E out = GM / x2(x > R)

E in = G Mx / R3( x > R)


Variation ofgdue to heightg’ = g (1 – h /R) if h <

G’ g / (1 + h / R)2ifhis comparable toR

Variation ofgdue to depth

g’ = g (1 – x/ R)wherexis the depth.

= Oat the centre of the earth

Variation of g with rotation of earth/ latitude

G’ = g (1 – Rω2/ g cos2λ)

That isgis maximum at the poles and minimum at the equator

Orbital velocityv0√(G )M / r

Wherev0速度是一个地球啊r a satellite moves in its orbit andris the radius of the orbit.

Escape velocityv0= √2GM / r

Escape velocity is the minimum velocity required to escape from the surface of the earth/planet from its gravitational field.

Time period T = 2 πr /v0或T2 = 4π2 r3 /通用

Kinetic energy KE= 1/2 m
v02= GMm / 2a, PE= - GM(m / a)

Net energy E = KE+ PE= - GMm/2a note ve= √2
v0.

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